Sum of integers from 1 to 100 which are divisible by 2 or 5. The multiples of 3 up to 100 are 3, 6, 9, .

Sum of integers from 1 to 100 which are divisible by 2 or 5. 83M subscribers 216 The sum of the integers from 1 to 100 that are divisible by 2 or 5 is (a) 3000 (b) 3050 (c) 4050 (d) None of these. IQ Math - Preparatory Problems and Solutions for Higher Level Competitive Exams - Grade Jul 6, 2021 · Find an answer to your question Find the sum of integers from 1 to 100 that are divisible by 2 or 5. 2838 D. 2489. The requested sum is . e. 10,050 B. Here’s a step-by-step solution: - A be the set of integers from 1 to 100 that are divisible by 2. View Solution VIDEO ANSWER: in discussion we have to find us some of all oriented occurs between two and 100 which are divisible by three. The below workout with step by step calculation shows how to find what is the sum of first 20 positive integers which are divisible by 5 by applying arithmetic progression. step 1 Input Parameters and values: The number series 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100, . ⇒ n = 20 The integers, which are divisible by both 2 and 5, are 10, 20, … 100. 1050 C. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Find the sum of the integers between 100 and 200 that are (i) divisible by 9 (ii) not divisible by 9. The formula for the sum of the first n natural numbers is given by: Sn = n(n+1) 2 For n= 100: S100 = 100×101 2 = 5050 Step 2: Calculate the sum of multiples of 3 up to 100. Nov 19, 2024 · To find the sum of integers from 1 to 100 that are divisible by 2 or 5, we need to use the principle of inclusion and exclusion. Therefore, the correct answer to the question is option (b) 3050. The sum is (10/2) (10 + 100) = 550. First, calculate the sum of integers divisible by 2 and the sum of integers divisible by 5, then subtract the sum of integers divisible by both 2 and 5 (which is divisible by 10, so you don't double-count it). The sum of all odd integers between 2 and 100 divisible by 3 is 867. Using formula find the number of ter ☛ Related Questions: Find the sum of the integers between 100 and 200 that are divisible by 9 Find the sum of the integers between 100 and 200 that are not divisible by 9 The ratio of the 11th term to the 18th term of an AP is 2 : 3. Calculate the number of terms using the formula [ (last term - first term)/7] + 1, then apply the sum of an arithmetic sequence formula. Apr 22, 2023 · What is the sum of all integers from 1 to 1000 that are divisible by both 3 and 5? A. of numbers by 2 and the r Oct 30, 2023 · Class 11 Mathematics Sequences and Series Arithmetic progression The sum of integers from 1 to 100 that are divisible by 2 or 5 Question Hard Solving time: 4 mins Jul 23, 2025 · Even numbers are those numbers that are exactly divisible by 2. 8k points) selected Jan 16, 2020 by Ritik01 Best answer Correct option (B) 3050 The sum of integers from 1 to 100 that are divisible by 2 or 5 = sum of series divisible by 2 + sum of series divisible by 5 - sum of series divisible by 2 and 5 = 2550 + 1050 - 550 = 3050 ← Prev Question Next Question → Jan 3, 2015 · Hence, the integers from 1 to 100, which are divisible by both 2 and 5 are 10, 20, …. This also forms an A. The sum of integers from 1 to 100 that are divisible by 2 or 5 is 1) 3000 2) 3050 3) 3100 4) 3150 54. 550 B. Understand the Sum of integer’s formula using solved examples. The integers divisible by 10 are 10, 20, 30, , 100. Answer is 1683. What is the remainder when 38 dozen is divided by 7? One way to solve this is to multiply 38 by 12 then divide by 7: For part (i), integers divisible by 2 and 3 means integers divisible by the LCM of 2 and 3, which is 6. First term = a = 2 common difference Now, we have to subtract the sum of the integers which are added twice that are the numbers divisible by 2 × 5 = 10. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. σ (N) is the Divisor Function. This means the first number divisible by 3 is 21 bec use 2 + 1 = 3. . It's one of the easiest methods to quickly find the sum of given number series. Here’s a step-by-step solution: Correct option is B. Thus, the correct answer is Option A. Jul 30, 2024 · The sum of integers from 1 to 100 that are divisible by 2 or 5 is 3050, computed by adding the sums of multiples of 2 and 5 while subtracting the sum of common multiples of 10 to avoid double counting. 3848 E. In an increasing sequence of 10 Question From - NCERT Maths Class 11 Chapter 9 MISCELLANEOUS EXERCISE Question – 5 SEQUENCES AND SERIES CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-Find th The sum of integers lying between 1 and 100 and are divisible by 3 or 5 or 7 is: (a) 2838 (b) 3468 (c) 2738 (d) 3368. The largest integer less than or equal to 100 that is divisible by 15 is 90. s (N) is the Restricted Divisor Function. Examples: Input: A = 25, B = 100, M = 30 Output: 180 Explanation: In the given range [25, 100] 30, 60 and 90 are the numbers which are divisible by M = 30 Therefore, sum of these numbers = 180. It represents the sum of the proper divisors of n, excluding n itself. The Obtain the sum of all positive integers up to 1000, which are divisible by 5 and not divisible by 2. Using the inclusion-exclusion principle, find the number of integers from a set of 1-100 that are not divisible by 2, 3 and 5. Find the ratio of the 5th term to the . Arithmetic Progression (A. 4375 c. Aug 4, 2022 · Find an answer to your question find the sum of integers from 100 to 500 that are divisible by 2 and 3 Aug 28, 2011 · The sum of the numbers which are divisible by $3$ in this range is $$ 3+6+\cdots+99=3 (1+2+\cdots+33) $$ and likewise the sum of those divisible by $5$ is $$ 5+10+\cdots+100=5 (1+2+\cdots+20). Apply the principle of inclusion-exclusion. Aug 8, 2020 · Answer: There are 264 integers between 1 and 566 divisible by either 3 or 5. How the last number is 99? We get answer as 99. (K) (25,000) A. 100 This also forms an A. Thus, the sum of the integers from 1 to 100, which are divisible by 2 or 5, is 3050. 2849 b. The sum of these numbers is 21 + 51 3. . 33165 B. $$ You should be aware of a quick formula to add these two sums. For each iteration, check whether i is divisible by 3 or 4 using the modulo operator %. If , then is half of an integer, and letting for some integer gives Thus divides . May 5, 2018 · what is the sum of the integers from 1 to 100 which are not divisible by 3 or 5 - 3542309 Dec 9, 2018 · K = sum of the integers from 1 to 500 inclusive that are divisible by 5. The old in teasers come on between two 1000. Get the list of even numbers from 1 to 100, their properties, and difference from odd numbers in this article. Ans: Hint: First of all find the sum of integers which are divisible by 3 then find the sum of integers which are divisible by 5 and al Jun 2, 2020 · there are 20 numbers divisible by 5 and 33 numbers divisible by 3 so the total numbers which are divisible by both 3 and 5 between 1 to 100 are 20+33=53 numbers. Oct 30, 2023 · To find the sum of integers from 1 to 100 that are divisible by 2 or 5, you can use the principle of inclusion-exclusion. 3050 The numbers between 1 to 100 that are divisible by 2 are, Click here👆to get an answer to your question ️ Find the sum of integers from 1 to 100 that are divisible by 2 or 5. Check Answer and Solution for above question To solve this problem, we need to find the sum of integers from 1 to 100 that are divisible by 2 or 5. In this case, the common difference is 2 since we are considering only even numbers, and the first term is 2 since 1 is not divisible by 2. ) Is there an error in this question or solution? Find the Sum of Integers from 1 to 100 that Are Divisible by 2 Or 5. For part (i), integers divisible by 2 and 3 means integers divisible by the LCM of 2 and 3, which is 6. 26323. Solution:- If the number must be divisible by 3, so first number between 2 and 100 is 3, and the last number is 99. To find the sum of integers from 1 to 100 that are divisible by 2 or 5, we can follow these steps: Step 1: Find the sum of integers divisible by 2 The integers divisible by 2 from 1 to 100 form an arithmetic progression (AP): - First term (a) = 2 - Common difference (d) = 2 - Last term (l) = 100 To find the number of terms (n) in this AP, we use the formula for the nth term of an AP: an =a+(n The sum of integers from 1 to 100 which are divisible by 2 or 5 is (1) 300 (2) 3050 (3) 3200 (4)3250 hemeluomial function on Solution Verified by Toppr Solutions for The sum of integers from 1 to 100 which are divisible by 2 or 5 isa)3000b)3010c)3150d)3050Correct answer is option 'D'. Sum of integers from 1 to 100 that are divisible by 2 is a, by 5 is b and by both 2 and 5 is c. by Maths experts to help you in doubts & scoring excellent marks in Class 12 exams. 3050 The numbers between 1 to 100 that are divisible by 2 are, The sum of integers from 1 to 100 which is not divisible by 3 or 5 is a. Inclusion-Exclusion Principle: To find the sum of integers divisible by 2 or 5, we can find the sum of integers divisible by 2, add the sum of integers divisible by 5, and then subtract the The sum of all whole numbers 1 to 100 can be calculated using the formula, S= n/2 [2a + (n − 1) × d], where n = total number of whole numbers from 1 to 100, d = common difference between the two consecutive terms, and a = first term. Jul 3, 2023 · Question Using the inclusion-exclusion principle, find the number of integers from a set of 1-100 that are not divisible by 2, 3 and 5. M of two numbers is greater than G. Thanks to Gauss, we know that the Similar questions Q. If A. The sum of the integers from 1 to 100 which are divisible by 3 and 5 is:1. 5,000 D. To find the sum of integers from 1 to 100 that are not divisible by 3 or 5, we will follow these steps: Step 1: Calculate the sum of the first 100 natural numbers. Solution • The sum of first hundred positive integer = 100∗(100+1) 2 = 50 ∗ 101 = 2 ∗52 ∗ 101 = 100 ∗ (100 + 1) 2 = 50 ∗ 101 = 2 ∗ 5 2 ∗ 101 • Therefore, out of the given choices, the sum of first hundred positive integers is divisible by 2 only. To find:- The sum of all integers between 2 and 100 which are divisible by 3. Ans: Hint:Here, for the first part write all terms between 100 to 200 divisible by 9, these terms form an A. We will find the sum of multiples of 2, the sum of multiples of 5, and subtract the sum of multiples of 10 (since these are counted twice). This series will form an arithm Text solution Verified Solutions Question 1: Sum of integers from 1 to 100 that are divisible by 2 or 5 To find the sum of integers from 1 to 100 divisible by 2 or 5, use inclusion-exclusion principle. The sum of integers divisible by 2 or 5 is the sum of integers divisible by 2 plus the sum of integers divisible by 5 minus the sum of integers divisible by both 2 and 5. in/question/12947068 Explore all similar answers arrow right heart outlined Jul 23, 2025 · Even numbers are those numbers that are exactly divisible by 2. Jul 7, 2020 · =27150 27150 is sum of integers from 1 to 300 which are divisible by 2 or 5 Learn more: The sum of all integers between 200 and 800, which is divisible by 9 brainly. 4848 ­ Jan 14, 2020 · vote answered Jan 14, 2020 by KumariJuly (52. Jul 16, 2020 · The following Question is a part of Arithmetic Progression. This is an arithmetic series with first term 10, last term 100, and common difference 10. Check Answer and Solution for above question Find the sum of all integers from 1 and 100 that are divisible by 2 or 5. The multiples of 3 up to 100 are 3, 6, 9, , 99. What is the sum of integers from 1 to 100 that are divisible by 2 or 5? A. Ans: Hint: Here, we will write the series of the integers divisible by 2, divisible by 5, and divi Mar 12, 2020 · What is the sum of the integers between 1 and 100, inclusive, which are divisible by 3 or 5 or 7? A. 55,000 Calculate the sum of integers divisible by 15 (the least common multiple of 3 and 5). - B be the set of integers from 1 to 100 that are divisible by 5. Find the sum of integers from 1 to 100 that are divisible by 2 or 5. 50,000 E. This is . We can use the formula for the sum of an arithmetic series to find their sum: Sum = (number of terms / 2) * (first term + last term) Sum = (50 / 2) * (2 + 100) Sum = Show more… Dec 9, 2018 · K = sum of the integers from 1 to 500 inclusive that are divisible by 5. 818 B. Count (d (N)) is the number of positive divisors of n, including 1 and n itself. The smallest is 2 and the largest is 100. multiple of 3. , divisible by 10) are: Step 3: Calculate the sum of integers divisible by 10. LCM of 2 and 3. 3154. Hence, we have obtained the sum of integers from 1 to 100 which are divisible by 2 or 5 as 3050. Sep 4, 2023 · To find the sum of all integers between 100 and 400 divisible by 7, first find the first and last terms that are divisible by 7 (105 and 399). in/question/12590445 find the sum of all integers from 100 to 400, which are divisible by brainly. The sum is S₁₀ = (10/2) (10 + 100) = 5 * 110 = 550. Jun 2, 2020 · there are 20 numbers divisible by 5 and 33 numbers divisible by 3 so the total numbers which are divisible by both 3 and 5 between 1 to 100 are 20+33=53 numbers. It represents the sum of all the positive divisors of n, including 1 and n itself. with both the first term and common difference equal to 10. The number of terms is 100/10 = 10. P. This is how we choose the last term as 99 Now we have So, we have to find Find the sum of the following arithmetic progression: (x-y)^2, (x^2+y^2), (x+y)^2, to n terms Find the sum of all even integers between 101 and 999. The quantity in Column A is greater B. 33466 D. The sum of integers from 1 to 100 that are divisible by 2 or 5 is Doubtnut 3. The sum of integers from 1 to 100 that are divisible by 2 or 5 , is (A) 3000 (B) 3056 (C) 3050 (D) 3060. Be careful to add back all the numbers that are divisible by $15$, as they have been subtracted twice. The other two numbers will be 51 and 81 because 5 + 1 = 6 and 8 + 1 = 9. - 37942121 Oct 22, 2023 · The sum of all integers from 1 to 1000 that are divisible by 2 but not by 5 can be found using the arithmetic sequence formula. Sum of integers which are divisible by 2 or 3 from 1 to 100 =(Sum of integers which are divisible by 2 from 1 to 100)+ (Sum of integers which are divisible by 3 from 1 to 100) (Sum of integers which are divisible by 6 from 1 to 100) Jul 30, 2024 · The sum of integers from 1 to 100 that are divisible by 2 or 5 is 3050, computed by adding the sums of multiples of 2 and 5 while subtracting the sum of common multiples of 10 to avoid double counting. 2317 d. as First term = a =2 common difference d =4−2 =2 Last term = l = 100 2,4,6,8,…. Sum of integers from 1 to 100 divisible by 2 or 5 = 2550 + 1050 - 550 = 2550 + 500 = 3050 Correct option is B. Numbers without fractional components are integers, if it is required to add many consecutive integers at a time, we a use sum of integers formula. 5,050 C. The quantity in Column B is greater C. For part (ii), integers divisible by 2 or 3 means the union of multiples of 2 and multiples of 3, summed without double counting those divisible by both (i. Mar 29, 2021 · The sum of integers from 1 to 100 which are not divisible by 3 or 5 is. Jul 6, 2021 · Find an answer to your question Find the sum of integers from 1 to 100 that are divisible by 2 or 5. Jul 11, 2025 · Use a for loop to iterate from 1 to n, where the variable i is the loop counter. Step-by-step explanation: 3 is the first number from 1 to 566 divisible by 3 and the last one is 564. 23172. Jul 27, 2018 · Sum of integers between 1 to 100 divisible by 2 or 5 Get the answers you need, now! Ideas for Solving the Problem Sum of an Arithmetic Series: The sum of an arithmetic series is given by S = (n/2) (a_1 + a_n), where n is the number of terms, a_1 is the first term, and a_n is the last term. To find the sum of integers from 1 to 100 that are divisible by 2 or 5, we can use the principle of inclusion-exclusion. 100 Number of terms = n= 100 2 = 50 S50 = 50 2[2+100] ⇒ S50 = 50 2[102] S50 = 50 2[102] S50= 50×51 ⇒ Jul 12, 2025 · Given three numbers A, B and M such that A < B, the task is to find the sum of numbers divisible by M in the range [A, B]. The only divisors for a Prime Number are 1 and Those are multiple of 6 i. 33333 C. A. The two quantities are equal D. 3050 Ans: D 14. , multiples of 6). For a Prime Number, Count (d (N))=2. 1828 C. The sum of the numbers from 1 to 100 that satisfy these conditions is 1050. 2550 D. Step 3: Find the sum of integers that are counted twice (divisible by both 2 and 5) The integers that are divisible by both 2 and 5 (i. Step 1: Finding sum of integers from 1 to 100 divisible by 2. Integers divisible by 2 between 1 to 100 are 2,4,6,8,…100 This is an A. ∴100 = 10 + (n –1) (10) ⇒ 100 = 10n ⇒ n = 10 ∴Required sum = 2550 + 1050 – 550 = 3050 Thus, the sum of the integers from 1 to 100, which are divisible by 2 or 5, is 3050. It follows that , and . 2632 Nov 7, 2019 · Find the sum of integers from 1 to 100 that are divisible by 2 or 5. The solution to the sum of all integers from 1 and 100 that are divisible by 2 or 5 is 3050. We want to find the sum of the elements in A∪B. 33766 Jul 21, 2023 · Step by step video & image solution for Find the sum of integers from 1 to 100 that are divisible by 2 or 5. Find the sum of integers which are divisible 2 or 5. Input: A = 6, B = 15, M = 3 Output: 42 Explanation: In the given range [6, 15 Aug 20, 2016 · ⇒ n = 20 The integers, which are divisible by both 2 and 5, are 10, 20, … 100. Ans: Hint: Here we will write the series of the integers that are divisible by 3, divisible by 5 and divisible by 15. ∴100 = 10 + (n –1) (10) ⇒ 100 = 10 n ⇒ n = 10 ∴Required sum = 2550 + 1050 – 550 = 3050 Thus, the sum of the integers from 1 to 100, which are divisible by 2 or 5, is 3050. of numbers by 2 and the r Oct 30, 2023 · Class 11 Mathematics Sequences and Series Arithmetic progression The sum of integers from 1 to 100 that are divisible by 2 or 5 Question Hard Solving time: 4 mins Click here👆to get an answer to your question ️ The sum of integers from 1 to 100 which are divisible by 2 or 5 is? Feb 1, 2025 · Sum of numbers (not divisible by 7) = Sum of all numbers in the range - Sum of numbers (divisible by 7) To find sum of all numbers in a range and numbers divisible by 7 cannot be performed within one A. To find the sum of integers from 1 to 100 that are divisible by either 2 or 5, we can use the principle of inclusion-exclusion. Solution 3 (Official MAA 2) The sum of the cubes of the integers from through is which, when divided by , has quotient with remainder If is not congruent to , then is an integer, and so divides , and . These are the even numbers, and there are 50 of them. Apr 14, 2024 · The question asks us to find how many integers between 100 and 999 meet two specific conditions: the sum of the integer's digits is evenly divisible by 3 (condition 1), and the integer itself is not divisible by 9 (condition 2). We can use the principle of inclusion-exclusion for this. M. 33500 E. This is 2550 + 1050 - 550 = 3050 مفيد غير مفيد شرح بسّط هذه الحلّة Find the sum of integers from 1 to 100 that are divisible by 2 or 5. , divisible by 10) are: Oct 22, 2023 · To find the sum of **integers **divisible by 5 but not by 2, we use the concept of arithmetic progression. undn yjld apkh0p zfvx 08b bibr stqxqp f3b mnokg rhz